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Statistics Help

Question: Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Of 346 items tested, 12 are found to be defective. Construct the 98% confidence interval for the proportion of all such items that are defective  Edit

Answer: n=346
p_bar=12/346 =0.0347
1-p_bar=0.9653
Z value for 98% CI =2.33
and compute E ? 0.0229 ,
The confidence interval is
0.0118 < p < 0.0576  Edit


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