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Question: Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid water (H2O) . Suppose 2.43 g of hydrobromic acid is mixed with 1.9 g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the chemical reaction. Round your answer to 3 significant digits. Edit
Answer: HBr+NaOH--> NaBr+ H2O
1 mol HBr reacts with 1 mol of NaOH to produce 1 mol of NaBr and 1 mol of H2O
80.91 gm of HBr= 1 mol HBr
2.43 gm of HBr= 0.03 mol
40gm NaOH= 1 mol
1.9 gm NaOH= 0.047 mol
Amount of NaOH in mol is higher than that of HBr. That means max to max 0.03 mol of each NaOH and HBr will react to produce 0.03 mol of NaBr.
1 mol NaBr= 102.9 gm of NaBr
0.03 mol NaBr= 3.087 gm of NaBr
3.087 gm of NaBr could be produced. Edit
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