Statistics Help
Question: the length of life of a certain type of washer is approximately normal distributes with a mean=3.3 years and standard deviation 1.3 years. If this washer is guaranteed for 1 yr, what fraction of the sales will require replacements. Edit
Answer: Given X~Normal(mean=3.3, s=1.3)
So the probability is
P(X>1)=P((X-mean)/s >(1-3.3)/1.3)
=P(Z>-1.77)
=0.9616 (check standard normal table) Edit
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