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Statistics Help

**Question: **A survery of college students was taken to determine what percentage of students would be voting in the upcoming elections. The results were stated as 66% with a margin of error of plus/minus 5%. What is meant by plus/minus 5%?

a)In the sample, the percentage of college students who plan to vote is between 61% and 71%

b) The percentage of the entire population of college students who plan to vote in the upcoming elections is between 61% and 71%

c) It is unlikely that the given sample propotion would be obtained unless the true percentage of college students who planned to vote in the upcoming elections was between 61% and 71%

Edit

**Answer: **Ans:

a) mean=0.66 ,

margin of error, e=sd/sqrt(n)*z_c=standard error*critical z=0.05

standard error=0.05/1.96 [critical z at 95% confidence.]=0.025

x bar=0.61 , the z= (0.61-0.66)/0.025=-2

x bar=0.71 , the z= (0.71-0.66)/0.025=+2

P(0.61

=0.9544=95.44%(Ans.) Edit

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