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## A dump of our free Chat sessions, in case it is useful. It excludes white boards used during paid sessions.

student : let the function h be defined j(x) = 4x+3. if 1/3j(radicalr)=3 what is the value of r?
student : I dont understand it at all
student : Sorry its " let the function J be defines j(x) and so on
student : SOrrrrry
student : Its the square root sign
student : with r in it
student : Okay
student : Let the function j be defined by j(x)=4x+3
student : If 1/3 j (the sqaure root of r) = # hat is the value of r?
tutor3 : = to what?
student : = 3
student : What is the value of r
tutor3 : r=4.63
student : The choices are 4 / (the square root of 3)
student : 3/4 (the square root of 3)
student : 6/4
student : 9/4
student : 3
student : 4.63 is not one of the choices.
tutor3 : .is it 1/(3*j(sqrtr)=3
student : Yes
tutor3 : means 3*j(sqrt(r)is fully in the denominator right?
student : no it says "if 1/3J * (square root of r) = 3
student : What is the value of r
tutor3 : ok
student : Okay
student : How did you get that?
tutor3 : you use hte function j(x)=4x+3
tutor3 : so j(sqrtr)=4*(sqrt(r)+
tutor3 : 3
tutor3 : so 4*(sqrtr)+3=(1/9)
tutor3 : then you solve for r

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