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tutorsd6 : Please, share your Math problem...
student : A particle moves along the curve given by y=(t^3+1)^1/2 Find the acceleration of the particle at time t=2 seconds.

A 5 meter ladder is leaning against the side of a house. The foot of the ladder is pulled away from the house at a rate of 4 meters per second. Determine how fast the top of the ladder is descending when the foot of the ladder is 3 meters from the house.

Cone--20 ft/min, Altitude is three times greater that diameter. What is the rate of pile changing at 12 ft high?

Differentiate::
f(x)=(2x^2+5)^7
y=(X^2)^1/3 + x
f(x)=1/(3-x^3)^1/3
y=cot (x)^1/3
f(x)=(sin2x)^1/2
g(x)=sec(x^1/2)

Determine the slope of the graph of 2x^2 -3xy+y^3=-1 at (2,-3)
Given f(x)=(1-y)/(2-x), find f'(x)
Find dy/dx for the equation y (-x)/(x+y)
tutorsd6 : Please send the question to us : tutor@aafter.com
or call Phone: 866-930-6363
We will send you the solution to your mail within 2/3 hours .



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