# Percentage Problem 16

### From Homeworkwiki

**An increase of 10 % in the price of sugar compels to buy 1 kg sugar less for $ 220. Find:**

**(i) the original price per kg of the sugar;**

**(ii) the increased price per kg of the sugar.**

**Solution:** (i) Let the original price of one kg sugar = $ x

=> The original quantity of sugar bought for $ 220 = 220 / x kg

Now, the new price of one kg sugar = $ x + 10 % of $ x

= $ (x + 10 x / 100) = $ 11 x / 10

Therefore, the new quantity of sugar bought for $ 220 = $ 220 X 10 / 11 x kg = 220 / x kg

Given, 220 / x - 200 / x = 1

=> (220 - 200) / x = 1

=> x = 20

Therefore, the original price per kg of sugar = **$ 20**

(ii) The increased price per kg of sugar = $ 11 x / 10

= $ (11 X 20) / 10 = **$ 22**