Percentage Problem 16

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An increase of 10 % in the price of sugar compels to buy 1 kg sugar less for $ 220. Find:

(i) the original price per kg of the sugar;

(ii) the increased price per kg of the sugar.

Solution: (i) Let the original price of one kg sugar = $ x

=> The original quantity of sugar bought for $ 220 = 220 / x kg

Now, the new price of one kg sugar = $ x + 10 % of $ x

= $ (x + 10 x / 100) = $ 11 x / 10

Therefore, the new quantity of sugar bought for $ 220 = $ 220 X 10 / 11 x kg = 220 / x kg

Given, 220 / x - 200 / x = 1

=> (220 - 200) / x = 1

=> x = 20

Therefore, the original price per kg of sugar = $ 20

(ii) The increased price per kg of sugar = $ 11 x / 10

= $ (11 X 20) / 10 = $ 22

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