Number Problem 8

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The sum of three consecutive integers is –12. Find the three integer?

Solution: Let the three consecutive integers be (n-1), n, (n+1).

Given, (n-1) + n + (n+1) = -12

Therefore, 3n = -12

Dividing both sides of the equality by 3, we get

3n/3 = -12/3

Implies, n = -4
Hence, the three integers are (-4 - 1), (-4) and (-4+1)
i.e., -5, -4 and -3.

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