Mensuration-28

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A copper wire, when bent in the form of a square, encloses an area of 484 cm2. If the same wire
is bent in the form of a circle, find the area enclosed by it.

Solution: Area of the square = 484 cm2

Therefore, side of the square = √484 cm = 22 cm

=> Perimeter of the square = 4 x side = 4 x 22 = 88 cm

This is the length of the circumference of the circle formed by bending the wire.

Let r be the radius of this circle, then

2 Π r = 88; i.e. 2 x 22 / 7 x r = 88; r = 14 cm

Therefore, Area of the circle = Π r2 = (22 / 7 x 142) cm2 = 616 cm2

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