Logarithms-23

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Using logarithms, evaluate each of the following :

(i) (5.26) 3 (ii) (0.078) 4

Solution:

(i) Let x = (5.26) 3

=> log x = log (5.26) 3

= 3 log 5.26 [log a m = m log a]

= 3 X 0.7210 = 2.1630

=> x = antilog 2.1630 = 145.5

(ii) Let x = (0.078) 4

=> log x = 4 log 0.078 = 4 X ‾2.8921

= ‾5.5684

=> x = antilog ‾5.5684

= 0.00003701

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