Logarithms-18

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If log 2 = 0.3010 and log 3 = 0.4771 , find the value of :

(i) log 6 (ii) log 5 (iii) log √ 24

Solution :

(i) log 6 = log (2 X 3) = log 2 + log 3 = 0.3010 + 0.4771 = 0.7781

(ii) log 5 = log 10 / 2 = log 10 - log 2 = 1 - 0.3010 = 0.6990 [log 10 = 1]

(iii) log √ 24 = log ( 24 ) 1 / 2 = 1 / 2 log (2 3 X 3)

= 1 / 2 [3 X log 2 + log 3]

= 1 / 2 [3 X 0.3010 + 0.4771]

= 0.69005

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