# Logarithms-12

### From Homeworkwiki

**Find : (i) the logarithm of 1000 to the base 10**

**(ii) the logarithm of 1 / 9 to the base 3**

**Solution :**

(i) Let log _{10} 1000 = x

=> 10 ^{x} = 1000

=> 10 ^{x} = 10 ^{3}

=> x = 3

Therefore, **log _{10} = 3**

(ii) Let log _{3} 1 / 9 = x

3 ^{x} = 1 / 9

=> 3 ^{x} = 3 ^{-2}

=> x = - 2

Therefore, **log _{3} 1 / 9 = **- 2