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**Prove that 1/log**_{3} 60 + 1/log_{5} 60 + 1/log_{4} 60 = 1

**Solution:** We know that log_{b} a = 1/log_{a} b

Therefore, 1/log_{3} 60 + 1/log_{5} 60 + 1/log_{4} 60

= log_{60} 3 + log_{60} 5 + log_{60} 4 = log_{60} 3 x 4 x 5

= log_{60} 60 = 1