# Linear Equation 17

### From Homeworkwiki

**Two articles A and B together cost $ 2,226. If article A costs 10 % more than B, find the cost of each article.**

**Solution:**

Let the cost of article B be $ x

Therefore, the cost of article A = $ (x + 10 % of x)

= (x + 10 x / 100 ) = $ 11 x / 10

Given, 11 x / 10 + x = 2,226

=> (11 x + 10 x) / 10 = 2,226

=> 21 x / 10 = 2,226

=> x = 2,226 X 10 / 21 = 1,060

Therefore, **the cost of article A** = $ 11 x / 10 = $ ( 11 X 1,060 ) / 10 = **$ 1,166**

and, **the cost of article B** = $ x = **$ 1,060**