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**Write a in terms of b for: a = 9**^{x} + 5 and b = 3 - 3^{x}

**Solution:** b = 3 - 3^{x}

=> 3^{x} = 3 - b

And, a = 9^{x} + 5

=> a = (3^{2})^{x} + 5

=> a = (3^{x})^{2} + 5

By replacing value of 3^{x} in a , we get a in terms of b as:

a = (3 - b)^{2} + 5