# Coordinate Geometry-5

### From Homeworkwiki

**Show that the triangle formed by the points A(-2, 0), B(2, 0), C(0, 2√3) is equilateral.**

**Solution:** AB^{2} = (- 2 - 2)^{2} + (0 - 0)^{2} = (-4)^{2} = 16

AC^{2} = (-2 - 0)^{2} + (0 - 2√3)^{2} = (-2)^{2} + (-2√3)^{2} = 4 + 12 = 16

BC^{2} = (2- 0)^{2} + (0 - 2√3)^{2} = 4 + 12 = 16

Therefore, AB^{2} = AC^{2} = BC^{2}

Therefore, AB = AC = BC