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Question: A city council is considering drafting legislation related to the exclusion of renters with children. Since implementation will be expensive, they will only consider pro- ceeding if the true proportion of apartments that prohibit children is more than 75 percent. Suppose that out of 125 sampled appartments, 102 exclude renters with children.
a) What is the observed proportion of apartments which exclude renters with children ?
b) What is the true proportion of apartments which exclude renters with children ?
c) Compute the standard error of the observed proportion
d) Find the 95 percent confidence interval for the true proportion of apartments which exclude renters with children.
e) Is the 99 percent confidence interval wider or narrower than the 95 percent confidence interval ?  Edit

Answer: a) observed proportion = 102/125 = 0.816 (Ans.)  Edit

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