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Question: The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses. Assume that a sample of 450 college students was used in the study.

1) Provide both a 95% and a 99% confidence interval for the population proportion of college students who work to pay for tuition and living expenses. Edit

Answer: 1) p =0.47
n = 450
z_c= 1.96 at 95% confidence.

margin of error, E = sqrt(pq/n)*z_c
= sqrt(0.47*(1-0.47)/450)*1.96
= 0.0461

95% CI = (p - E, p + E)
= (0.47 - 0.0461, 0.47 + 0.0461)
= (0.4239, 0.5161) (Ans.) Edit

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