Ask any Statistics/Probability/Math or Any homework Question
Question: The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses. Assume that a sample of 450 college students was used in the study.
1) Provide both a 95% and a 99% confidence interval for the population proportion of college students who work to pay for tuition and living expenses. Edit
Answer: 1) p =0.47
n = 450
z_c= 1.96 at 95% confidence.
margin of error, E = sqrt(pq/n)*z_c
95% CI = (p - E, p + E)
= (0.47 - 0.0461, 0.47 + 0.0461)
= (0.4239, 0.5161) (Ans.) Edit
TutorTeddy.com & Boston Predictive Analytics
[ Email your Statistics or Math problems to firstname.lastname@example.org (camera phone photos are OK) ]
Boston Office (Near MIT/Kendall 'T'): Cambridge Innovation Center, One Broadway, 14th Floor, Cambridge, MA 02142, Phone: 617-395-8864