Mensuration-6
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A circular tent is in the form of a cylinder surmounted by a cone. If the common diameter
is 42 m, the height of the cylindrical portion be 6 m and the highest point of the roof 34 m
from the ground, find in square meters, the area of the canvas used in making the tent.
Solution: The curved surface area of the cylindrical portion = 2 π r h
= 2 x 22/7 x 21 x 6
= 792 sq. m
The height of the conical portion = 34 - 6 = 28 m
Therefore, the slant height of the cone = √(h2 + r2)
= √(282 + 212)
Hence, l = √(784 + 441) = √1225 = 35 m
The surface area of the conical portion of the tent = π r l
= 22/7 x 21 x 35 = 2310 sq. m
The area of the canvas used in making the tent = (2310 + 792) sq. m
= 3102 sq. m
