Logarithms-25
From Homeworkwiki
Evaluate :
(i) (6.32) 3 X (83.94) 1 / 4
(ii) [(17.42) 2 / 3 X 18.42] / (126.37) 1 / 2
Solution:
(i) Let x = (6.32) 3 X (83.94) 1 / 4
=> log x = 3 log 6.32 + (1 / 4) log 83.94
= 3 X 0.8007 + (1 / 4) X 1.9240
= 2.4021 + 0.4810
= 2.8831
=> x = antilog 2.8831 = 764.0
(ii) Let x = [(17.42) 2 / 3 X 18.42] / (126.37) 1 / 2
Therefore, log x = (2 / 3) log 17.42 + log 18.42 - (1 / 2) log 126.4
= (2 / 3) (1.2410) + 1.2653 - (1 / 2) (2.1018)
= 0.8273 + 1.2653 - 1.0509 = 1.0417
Therefore, x = antilog 1.0417 = 11.01



